1 /*
2  * CDDL HEADER START
3  *
4  * The contents of this file are subject to the terms of the
5  * Common Development and Distribution License, Version 1.0 only
6  * (the "License").  You may not use this file except in compliance
7  * with the License.
8  *
9  * You can obtain a copy of the license at usr/src/OPENSOLARIS.LICENSE
10  * or http://www.opensolaris.org/os/licensing.
11  * See the License for the specific language governing permissions
12  * and limitations under the License.
13  *
14  * When distributing Covered Code, include this CDDL HEADER in each
15  * file and include the License file at usr/src/OPENSOLARIS.LICENSE.
16  * If applicable, add the following below this CDDL HEADER, with the
17  * fields enclosed by brackets "[]" replaced with your own identifying
18  * information: Portions Copyright [yyyy] [name of copyright owner]
19  *
20  * CDDL HEADER END
21  */
22 /*
23  * Copyright 2004 Sun Microsystems, Inc.  All rights reserved.
24  * Use is subject to license terms.
25  */
26 
27 /*
28  * _D_cplx_div_rx(a, w) returns a / w with infinities handled according
29  * to C99.
30  *
31  * If a and w are both finite and w is nonzero, _D_cplx_div_rx(a, w)
32  * delivers the complex quotient q according to the usual formula:
33  * let c = Re(w), and d = Im(w); then q = x + I * y where x = (a * c)
34  * / r and y = (-a * d) / r with r = c * c + d * d.  This implementa-
35  * tion computes intermediate results in extended precision to avoid
36  * premature underflow or overflow.
37  *
38  * If a is neither NaN nor zero and w is zero, or if a is infinite
39  * and w is finite and nonzero, _D_cplx_div_rx delivers an infinite
40  * result.  If a is finite and w is infinite, _D_cplx_div_rx delivers
41  * a zero result.
42  *
43  * If a and w are both zero or both infinite, or if either a or w is
44  * NaN, _D_cplx_div_rx delivers NaN + I * NaN.  C99 doesn't specify
45  * these cases.
46  *
47  * This implementation can raise spurious invalid operation, inexact,
48  * and division-by-zero exceptions.  C99 allows this.
49  *
50  * Warning: Do not attempt to "optimize" this code by removing multi-
51  * plications by zero.
52  */
53 
54 #if !defined(i386) && !defined(__i386) && !defined(__amd64)
55 #error This code is for x86 only
56 #endif
57 
58 /*
59  * Return +1 if x is +Inf, -1 if x is -Inf, and 0 otherwise
60  */
61 static int
testinf(double x)62 testinf(double x)
63 {
64 	union {
65 		int	i[2];
66 		double	d;
67 	} xx;
68 
69 	xx.d = x;
70 	return (((((xx.i[1] << 1) - 0xffe00000) | xx.i[0]) == 0)?
71 		(1 | (xx.i[1] >> 31)) : 0);
72 }
73 
74 double _Complex
_D_cplx_div_rx(double a,double _Complex w)75 _D_cplx_div_rx(double a, double _Complex w)
76 {
77 	double _Complex	v;
78 	union {
79 		int	i[2];
80 		double	d;
81 	} cc, dd;
82 	double		c, d;
83 	long double	r, x, y;
84 	int		i, j;
85 
86 	/*
87 	 * The following is equivalent to
88 	 *
89 	 *  c = creal(w); d = cimag(w);
90 	 */
91 	/* LINTED alignment */
92 	c = ((double *)&w)[0];
93 	/* LINTED alignment */
94 	d = ((double *)&w)[1];
95 
96 	r = (long double)c * c + (long double)d * d;
97 
98 	if (r == 0.0f) {
99 		/* w is zero; multiply a by 1/Re(w) - I * Im(w) */
100 		c = 1.0f / c;
101 		i = testinf(a);
102 		if (i) { /* a is infinite */
103 			a = i;
104 		}
105 		/* LINTED alignment */
106 		((double *)&v)[0] = a * c;
107 		/* LINTED alignment */
108 		((double *)&v)[1] = (a == 0.0f)? a * c : -a * d;
109 		return (v);
110 	}
111 
112 	r = (long double)a / r;
113 	x = (long double)c * r;
114 	y = (long double)-d * r;
115 
116 	if (x != x || y != y) {
117 		/*
118 		 * x or y is NaN, so a and w can't both be finite and
119 		 * nonzero.  Since we handled the case w = 0 above, the
120 		 * only case to check here is when w is infinite.
121 		 */
122 		i = testinf(c);
123 		j = testinf(d);
124 		if (i | j) { /* w is infinite */
125 			cc.d = c;
126 			dd.d = d;
127 			c = (cc.i[1] < 0)? -0.0f : 0.0f;
128 			d = (dd.i[1] < 0)? -0.0f : 0.0f;
129 			x = (long double)c * a;
130 			y = (long double)-d * a;
131 		}
132 	}
133 
134 	/*
135 	 * The following is equivalent to
136 	 *
137 	 *  return x + I * y;
138 	 */
139 	/* LINTED alignment */
140 	((double *)&v)[0] = (double)x;
141 	/* LINTED alignment */
142 	((double *)&v)[1] = (double)y;
143 	return (v);
144 }
145