/* * CDDL HEADER START * * The contents of this file are subject to the terms of the * Common Development and Distribution License, Version 1.0 only * (the "License"). You may not use this file except in compliance * with the License. * * You can obtain a copy of the license at usr/src/OPENSOLARIS.LICENSE * or http://www.opensolaris.org/os/licensing. * See the License for the specific language governing permissions * and limitations under the License. * * When distributing Covered Code, include this CDDL HEADER in each * file and include the License file at usr/src/OPENSOLARIS.LICENSE. * If applicable, add the following below this CDDL HEADER, with the * fields enclosed by brackets "[]" replaced with your own identifying * information: Portions Copyright [yyyy] [name of copyright owner] * * CDDL HEADER END */ /* * Copyright 2004 Sun Microsystems, Inc. All rights reserved. * Use is subject to license terms. */ /* * _X_cplx_mul(z, w) returns z * w with infinities handled according * to C99. * * If z and w are both finite, _X_cplx_mul(z, w) delivers the complex * product according to the usual formula: let a = Re(z), b = Im(z), * c = Re(w), and d = Im(w); then _X_cplx_mul(z, w) delivers x + I * y * where x = a * c - b * d and y = a * d + b * c. Note that if both * ac and bd overflow, then at least one of ad or bc must also over- * flow, and vice versa, so that if one component of the product is * NaN, the other is infinite. (Such a value is considered infinite * according to C99.) * * If one of z or w is infinite and the other is either finite nonzero * or infinite, _X_cplx_mul delivers an infinite result. If one factor * is infinite and the other is zero, _X_cplx_mul delivers NaN + I * NaN. * C99 doesn't specify the latter case. * * C99 also doesn't specify what should happen if either z or w is a * complex NaN (i.e., neither finite nor infinite). This implementation * delivers NaN + I * NaN in this case. * * This implementation can raise spurious underflow, overflow, invalid * operation, and inexact exceptions. C99 allows this. */ #if !defined(i386) && !defined(__i386) && !defined(__amd64) #error This code is for x86 only #endif static union { int i; float f; } inf = { 0x7f800000 }; /* * Return +1 if x is +Inf, -1 if x is -Inf, and 0 otherwise */ static int testinfl(long double x) { union { int i[3]; long double e; } xx; xx.e = x; if ((xx.i[2] & 0x7fff) != 0x7fff || ((xx.i[1] << 1) | xx.i[0]) != 0) return (0); return (1 | ((xx.i[2] << 16) >> 31)); } long double _Complex _X_cplx_mul(long double _Complex z, long double _Complex w) { long double _Complex v = 0; long double a, b, c, d, x, y; int recalc, i, j; /* * The following is equivalent to * * a = creall(z); b = cimagl(z); * c = creall(w); d = cimagl(w); */ a = ((long double *)&z)[0]; b = ((long double *)&z)[1]; c = ((long double *)&w)[0]; d = ((long double *)&w)[1]; x = a * c - b * d; y = a * d + b * c; if (x != x && y != y) { /* * Both x and y are NaN, so z and w can't both be finite. * If at least one of z or w is a complex NaN, and neither * is infinite, then we might as well deliver NaN + I * NaN. * So the only cases to check are when one of z or w is * infinite. */ recalc = 0; i = testinfl(a); j = testinfl(b); if (i | j) { /* z is infinite */ /* "factor out" infinity */ a = i; b = j; recalc = 1; } i = testinfl(c); j = testinfl(d); if (i | j) { /* w is infinite */ /* "factor out" infinity */ c = i; d = j; recalc = 1; } if (recalc) { x = inf.f * (a * c - b * d); y = inf.f * (a * d + b * c); } } /* * The following is equivalent to * * return x + I * y; */ ((long double *)&v)[0] = x; ((long double *)&v)[1] = y; return (v); }